4(x+1)+6x=2(x+2)-8

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Solution for 4(x+1)+6x=2(x+2)-8 equation:



4(x+1)+6x=2(x+2)-8
We move all terms to the left:
4(x+1)+6x-(2(x+2)-8)=0
We add all the numbers together, and all the variables
6x+4(x+1)-(2(x+2)-8)=0
We multiply parentheses
6x+4x-(2(x+2)-8)+4=0
We calculate terms in parentheses: -(2(x+2)-8), so:
2(x+2)-8
We multiply parentheses
2x+4-8
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
We add all the numbers together, and all the variables
10x-(2x-4)+4=0
We get rid of parentheses
10x-2x+4+4=0
We add all the numbers together, and all the variables
8x+8=0
We move all terms containing x to the left, all other terms to the right
8x=-8
x=-8/8
x=-1

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