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4(x+1)+x=(3x-2)+2
We move all terms to the left:
4(x+1)+x-((3x-2)+2)=0
We add all the numbers together, and all the variables
x+4(x+1)-((3x-2)+2)=0
We multiply parentheses
x+4x-((3x-2)+2)+4=0
We calculate terms in parentheses: -((3x-2)+2), so:We add all the numbers together, and all the variables
(3x-2)+2
We get rid of parentheses
3x-2+2
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2
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