4(x+1)+x=3(x-2+2)

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Solution for 4(x+1)+x=3(x-2+2) equation: 



4(x+1)+x=3(x-2+2)

We move all terms to the left:

4(x+1)+x-(3(x-2+2))=0

We add all the numbers together, and all the variables

4(x+1)+x-(3(+x))=0

We add all the numbers together, and all the variables

x+4(x+1)-(3(+x))=0

We multiply parentheses

x+4x-(3(+x))+4=0



We calculate terms in parentheses: -(3(+x)), so:

3(+x)

We multiply parentheses

3x

Back to the equation:

-(3x)



We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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