4(x+1)+x=8(x+1)+6

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Solution for 4(x+1)+x=8(x+1)+6 equation: 



4(x+1)+x=8(x+1)+6

We move all terms to the left:

4(x+1)+x-(8(x+1)+6)=0

We add all the numbers together, and all the variables

x+4(x+1)-(8(x+1)+6)=0

We multiply parentheses

x+4x-(8(x+1)+6)+4=0



We calculate terms in parentheses: -(8(x+1)+6), so:

8(x+1)+6

We multiply parentheses

8x+8+6

We add all the numbers together, and all the variables

8x+14

Back to the equation:

-(8x+14)



We add all the numbers together, and all the variables

5x-(8x+14)+4=0

We get rid of parentheses

5x-8x-14+4=0

We add all the numbers together, and all the variables

-3x-10=0

We move all terms containing x to the left, all other terms to the right

-3x=10

x=10/-3

x=-3+1/3

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