4(x+1)-(2x-5)+16=2(3x+1)+(3x+1)

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Solution for 4(x+1)-(2x-5)+16=2(3x+1)+(3x+1) equation: 



4(x+1)-(2x-5)+16=2(3x+1)+(3x+1)

We move all terms to the left:

4(x+1)-(2x-5)+16-(2(3x+1)+(3x+1))=0

We multiply parentheses

4x-(2x-5)-(2(3x+1)+(3x+1))+4+16=0

We get rid of parentheses

4x-2x-(2(3x+1)+(3x+1))+5+4+16=0



We calculate terms in parentheses: -(2(3x+1)+(3x+1)), so:

2(3x+1)+(3x+1)

We multiply parentheses

6x+(3x+1)+2

We get rid of parentheses

6x+3x+1+2

We add all the numbers together, and all the variables

9x+3

Back to the equation:

-(9x+3)



We add all the numbers together, and all the variables

2x-(9x+3)+25=0

We get rid of parentheses

2x-9x-3+25=0

We add all the numbers together, and all the variables

-7x+22=0

We move all terms containing x to the left, all other terms to the right

-7x=-22

x=-22/-7

x=3+1/7

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