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4(x+1)-1=2(x-5)+2x+5
We move all terms to the left:
4(x+1)-1-(2(x-5)+2x+5)=0
We multiply parentheses
4x-(2(x-5)+2x+5)+4-1=0
We calculate terms in parentheses: -(2(x-5)+2x+5), so:We add all the numbers together, and all the variables
2(x-5)+2x+5
We add all the numbers together, and all the variables
2x+2(x-5)+5
We multiply parentheses
2x+2x-10+5
We add all the numbers together, and all the variables
4x-5
Back to the equation:
-(4x-5)
4x-(4x-5)+3=0
We get rid of parentheses
4x-4x+5+3=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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