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4(x+1)-3=1+(x-6)
We move all terms to the left:
4(x+1)-3-(1+(x-6))=0
We multiply parentheses
4x-(1+(x-6))+4-3=0
We calculate terms in parentheses: -(1+(x-6)), so:We add all the numbers together, and all the variables
1+(x-6)
determiningTheFunctionDomain (x-6)+1
We get rid of parentheses
x-6+1
We add all the numbers together, and all the variables
x-5
Back to the equation:
-(x-5)
4x-(x-5)+1=0
We get rid of parentheses
4x-x+5+1=0
We add all the numbers together, and all the variables
3x+6=0
We move all terms containing x to the left, all other terms to the right
3x=-6
x=-6/3
x=-2
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