4(x+1)-5(x-8)=10(x+3)

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Solution for 4(x+1)-5(x-8)=10(x+3) equation: 



4(x+1)-5(x-8)=10(x+3)

We move all terms to the left:

4(x+1)-5(x-8)-(10(x+3))=0

We multiply parentheses

4x-5x-(10(x+3))+4+40=0



We calculate terms in parentheses: -(10(x+3)), so:

10(x+3)

We multiply parentheses

10x+30

Back to the equation:

-(10x+30)



We add all the numbers together, and all the variables

-1x-(10x+30)+44=0

We get rid of parentheses

-1x-10x-30+44=0

We add all the numbers together, and all the variables

-11x+14=0

We move all terms containing x to the left, all other terms to the right

-11x=-14

x=-14/-11

x=1+3/11

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