4(x+1)-7=3(x-1)+x

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Solution for 4(x+1)-7=3(x-1)+x equation:


Simplifying
4(x + 1) + -7 = 3(x + -1) + x

Reorder the terms:
4(1 + x) + -7 = 3(x + -1) + x
(1 * 4 + x * 4) + -7 = 3(x + -1) + x
(4 + 4x) + -7 = 3(x + -1) + x

Reorder the terms:
4 + -7 + 4x = 3(x + -1) + x

Combine like terms: 4 + -7 = -3
-3 + 4x = 3(x + -1) + x

Reorder the terms:
-3 + 4x = 3(-1 + x) + x
-3 + 4x = (-1 * 3 + x * 3) + x
-3 + 4x = (-3 + 3x) + x

Combine like terms: 3x + x = 4x
-3 + 4x = -3 + 4x

Add '3' to each side of the equation.
-3 + 3 + 4x = -3 + 3 + 4x

Combine like terms: -3 + 3 = 0
0 + 4x = -3 + 3 + 4x
4x = -3 + 3 + 4x

Combine like terms: -3 + 3 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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