4(x+1)-8(x-3)=48

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Solution for 4(x+1)-8(x-3)=48 equation: 



4(x+1)-8(x-3)=48

We move all terms to the left:

4(x+1)-8(x-3)-(48)=0

We multiply parentheses

4x-8x+4+24-48=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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