4(x+1)=10-2(3-2x)

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Solution for 4(x+1)=10-2(3-2x) equation: 



4(x+1)=10-2(3-2x)

We move all terms to the left:

4(x+1)-(10-2(3-2x))=0

We add all the numbers together, and all the variables

4(x+1)-(10-2(-2x+3))=0

We multiply parentheses

4x-(10-2(-2x+3))+4=0



We calculate terms in parentheses: -(10-2(-2x+3)), so:

10-2(-2x+3)

determiningTheFunctionDomain
-2(-2x+3)+10

We multiply parentheses

4x-6+10

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

4x-4x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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