4(x+1)=3(x-3)-2(x-1)

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Solution for 4(x+1)=3(x-3)-2(x-1) equation: 



4(x+1)=3(x-3)-2(x-1)

We move all terms to the left:

4(x+1)-(3(x-3)-2(x-1))=0

We multiply parentheses

4x-(3(x-3)-2(x-1))+4=0



We calculate terms in parentheses: -(3(x-3)-2(x-1)), so:

3(x-3)-2(x-1)

We multiply parentheses

3x-2x-9+2

We add all the numbers together, and all the variables

x-7

Back to the equation:

-(x-7)



We get rid of parentheses

4x-x+7+4=0

We add all the numbers together, and all the variables

3x+11=0

We move all terms containing x to the left, all other terms to the right

3x=-11

x=-11/3

x=-3+2/3

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