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4(x+1)=3x+(2x-5)
We move all terms to the left:
4(x+1)-(3x+(2x-5))=0
We multiply parentheses
4x-(3x+(2x-5))+4=0
We calculate terms in parentheses: -(3x+(2x-5)), so:We get rid of parentheses
3x+(2x-5)
We get rid of parentheses
3x+2x-5
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
4x-5x+5+4=0
We add all the numbers together, and all the variables
-1x+9=0
We move all terms containing x to the left, all other terms to the right
-x=-9
x=-9/-1
x=+9
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