4(x+1)=6(x-3)+7

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Solution for 4(x+1)=6(x-3)+7 equation: 



4(x+1)=6(x-3)+7

We move all terms to the left:

4(x+1)-(6(x-3)+7)=0

We multiply parentheses

4x-(6(x-3)+7)+4=0



We calculate terms in parentheses: -(6(x-3)+7), so:

6(x-3)+7

We multiply parentheses

6x-18+7

We add all the numbers together, and all the variables

6x-11

Back to the equation:

-(6x-11)



We get rid of parentheses

4x-6x+11+4=0

We add all the numbers together, and all the variables

-2x+15=0

We move all terms containing x to the left, all other terms to the right

-2x=-15

x=-15/-2

x=7+1/2

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