4(x+1)=6(x-3)+7

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Solution for 4(x+1)=6(x-3)+7 equation:



4(x+1)=6(x-3)+7
We move all terms to the left:
4(x+1)-(6(x-3)+7)=0
We multiply parentheses
4x-(6(x-3)+7)+4=0
We calculate terms in parentheses: -(6(x-3)+7), so:
6(x-3)+7
We multiply parentheses
6x-18+7
We add all the numbers together, and all the variables
6x-11
Back to the equation:
-(6x-11)
We get rid of parentheses
4x-6x+11+4=0
We add all the numbers together, and all the variables
-2x+15=0
We move all terms containing x to the left, all other terms to the right
-2x=-15
x=-15/-2
x=7+1/2

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