4(x+1)=8(x+2)+4

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Solution for 4(x+1)=8(x+2)+4 equation: 



4(x+1)=8(x+2)+4

We move all terms to the left:

4(x+1)-(8(x+2)+4)=0

We multiply parentheses

4x-(8(x+2)+4)+4=0



We calculate terms in parentheses: -(8(x+2)+4), so:

8(x+2)+4

We multiply parentheses

8x+16+4

We add all the numbers together, and all the variables

8x+20

Back to the equation:

-(8x+20)



We get rid of parentheses

4x-8x-20+4=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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