4(x+1)=8(x+2)-12

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Solution for 4(x+1)=8(x+2)-12 equation: 



4(x+1)=8(x+2)-12

We move all terms to the left:

4(x+1)-(8(x+2)-12)=0

We multiply parentheses

4x-(8(x+2)-12)+4=0



We calculate terms in parentheses: -(8(x+2)-12), so:

8(x+2)-12

We multiply parentheses

8x+16-12

We add all the numbers together, and all the variables

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

4x-8x-4+4=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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