4(x+10)=3(9x-5)+20

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Solution for 4(x+10)=3(9x-5)+20 equation: 



4(x+10)=3(9x-5)+20

We move all terms to the left:

4(x+10)-(3(9x-5)+20)=0

We multiply parentheses

4x-(3(9x-5)+20)+40=0



We calculate terms in parentheses: -(3(9x-5)+20), so:

3(9x-5)+20

We multiply parentheses

27x-15+20

We add all the numbers together, and all the variables

27x+5

Back to the equation:

-(27x+5)



We get rid of parentheses

4x-27x-5+40=0

We add all the numbers together, and all the variables

-23x+35=0

We move all terms containing x to the left, all other terms to the right

-23x=-35

x=-35/-23

x=1+12/23

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