4(x+2)+1=2(x+4)=0

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Solution for 4(x+2)+1=2(x+4)=0 equation: 



4(x+2)+1=2(x+4)=0

We move all terms to the left:

4(x+2)+1-(2(x+4))=0

We multiply parentheses

4x-(2(x+4))+8+1=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

4x-(2x+8)+9=0

We get rid of parentheses

4x-2x-8+9=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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