4(x+2)+1=2x-3+3(x+4)

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Solution for 4(x+2)+1=2x-3+3(x+4) equation: 



4(x+2)+1=2x-3+3(x+4)

We move all terms to the left:

4(x+2)+1-(2x-3+3(x+4))=0

We multiply parentheses

4x-(2x-3+3(x+4))+8+1=0



We calculate terms in parentheses: -(2x-3+3(x+4)), so:

2x-3+3(x+4)

determiningTheFunctionDomain
2x+3(x+4)-3

We multiply parentheses

2x+3x+12-3

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We add all the numbers together, and all the variables

4x-(5x+9)+9=0

We get rid of parentheses

4x-5x-9+9=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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