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4(x+2)+2(-3x-3)=-3(2+2x)+2(2x+1)
We move all terms to the left:
4(x+2)+2(-3x-3)-(-3(2+2x)+2(2x+1))=0
We add all the numbers together, and all the variables
4(x+2)+2(-3x-3)-(-3(2x+2)+2(2x+1))=0
We multiply parentheses
4x-6x-(-3(2x+2)+2(2x+1))+8-6=0
We calculate terms in parentheses: -(-3(2x+2)+2(2x+1)), so:We add all the numbers together, and all the variables
-3(2x+2)+2(2x+1)
We multiply parentheses
-6x+4x-6+2
We add all the numbers together, and all the variables
-2x-4
Back to the equation:
-(-2x-4)
-2x-(-2x-4)+2=0
We get rid of parentheses
-2x+2x+4+2=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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