4(x+2)+2(x+1)=28

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Solution for 4(x+2)+2(x+1)=28 equation:


Simplifying
4(x + 2) + 2(x + 1) = 28

Reorder the terms:
4(2 + x) + 2(x + 1) = 28
(2 * 4 + x * 4) + 2(x + 1) = 28
(8 + 4x) + 2(x + 1) = 28

Reorder the terms:
8 + 4x + 2(1 + x) = 28
8 + 4x + (1 * 2 + x * 2) = 28
8 + 4x + (2 + 2x) = 28

Reorder the terms:
8 + 2 + 4x + 2x = 28

Combine like terms: 8 + 2 = 10
10 + 4x + 2x = 28

Combine like terms: 4x + 2x = 6x
10 + 6x = 28

Solving
10 + 6x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 6x = 28 + -10

Combine like terms: 10 + -10 = 0
0 + 6x = 28 + -10
6x = 28 + -10

Combine like terms: 28 + -10 = 18
6x = 18

Divide each side by '6'.
x = 3

Simplifying
x = 3

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