4(x+2)+2(x-1)=6(x+1)

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Solution for 4(x+2)+2(x-1)=6(x+1) equation: 



4(x+2)+2(x-1)=6(x+1)

We move all terms to the left:

4(x+2)+2(x-1)-(6(x+1))=0

We multiply parentheses

4x+2x-(6(x+1))+8-2=0



We calculate terms in parentheses: -(6(x+1)), so:

6(x+1)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

6x-(6x+6)+6=0

We get rid of parentheses

6x-6x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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