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4(x+2)+2(x-1)=6(x+1)
We move all terms to the left:
4(x+2)+2(x-1)-(6(x+1))=0
We multiply parentheses
4x+2x-(6(x+1))+8-2=0
We calculate terms in parentheses: -(6(x+1)), so:We add all the numbers together, and all the variables
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
6x-(6x+6)+6=0
We get rid of parentheses
6x-6x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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