4(x+2)+2x-4=8(x-2)+8

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Solution for 4(x+2)+2x-4=8(x-2)+8 equation:



4(x+2)+2x-4=8(x-2)+8
We move all terms to the left:
4(x+2)+2x-4-(8(x-2)+8)=0
We add all the numbers together, and all the variables
2x+4(x+2)-(8(x-2)+8)-4=0
We multiply parentheses
2x+4x-(8(x-2)+8)+8-4=0
We calculate terms in parentheses: -(8(x-2)+8), so:
8(x-2)+8
We multiply parentheses
8x-16+8
We add all the numbers together, and all the variables
8x-8
Back to the equation:
-(8x-8)
We add all the numbers together, and all the variables
6x-(8x-8)+4=0
We get rid of parentheses
6x-8x+8+4=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6

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