4(x+2)+3(7-x)=6(x+3)+1

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Solution for 4(x+2)+3(7-x)=6(x+3)+1 equation: 



4(x+2)+3(7-x)=6(x+3)+1

We move all terms to the left:

4(x+2)+3(7-x)-(6(x+3)+1)=0

We add all the numbers together, and all the variables

4(x+2)+3(-1x+7)-(6(x+3)+1)=0

We multiply parentheses

4x-3x-(6(x+3)+1)+8+21=0



We calculate terms in parentheses: -(6(x+3)+1), so:

6(x+3)+1

We multiply parentheses

6x+18+1

We add all the numbers together, and all the variables

6x+19

Back to the equation:

-(6x+19)



We add all the numbers together, and all the variables

x-(6x+19)+29=0

We get rid of parentheses

x-6x-19+29=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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