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4(x+2)+3(x+1)=2(x+3)
We move all terms to the left:
4(x+2)+3(x+1)-(2(x+3))=0
We multiply parentheses
4x+3x-(2(x+3))+8+3=0
We calculate terms in parentheses: -(2(x+3)), so:We add all the numbers together, and all the variables
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
7x-(2x+6)+11=0
We get rid of parentheses
7x-2x-6+11=0
We add all the numbers together, and all the variables
5x+5=0
We move all terms containing x to the left, all other terms to the right
5x=-5
x=-5/5
x=-1
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