4(x+2)+3(x+3)=7x+17

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Solution for 4(x+2)+3(x+3)=7x+17 equation: 



4(x+2)+3(x+3)=7x+17

We move all terms to the left:

4(x+2)+3(x+3)-(7x+17)=0

We multiply parentheses

4x+3x-(7x+17)+8+9=0

We get rid of parentheses

4x+3x-7x-17+8+9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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