4(x+2)+3(x+4)+1=0

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Solution for 4(x+2)+3(x+4)+1=0 equation: 



4(x+2)+3(x+4)+1=0

We multiply parentheses

4x+3x+8+12+1=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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