4(x+2)+3(x+4)=27

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Solution for 4(x+2)+3(x+4)=27 equation: 



4(x+2)+3(x+4)=27

We move all terms to the left:

4(x+2)+3(x+4)-(27)=0

We multiply parentheses

4x+3x+8+12-27=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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