4(x+2)+3(x-3)-35=6

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Solution for 4(x+2)+3(x-3)-35=6 equation: 



4(x+2)+3(x-3)-35=6

We move all terms to the left:

4(x+2)+3(x-3)-35-(6)=0

We add all the numbers together, and all the variables

4(x+2)+3(x-3)-41=0

We multiply parentheses

4x+3x+8-9-41=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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