4(x+2)+3x=7(x+1)+1

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Solution for 4(x+2)+3x=7(x+1)+1 equation:


Simplifying
4(x + 2) + 3x = 7(x + 1) + 1

Reorder the terms:
4(2 + x) + 3x = 7(x + 1) + 1
(2 * 4 + x * 4) + 3x = 7(x + 1) + 1
(8 + 4x) + 3x = 7(x + 1) + 1

Combine like terms: 4x + 3x = 7x
8 + 7x = 7(x + 1) + 1

Reorder the terms:
8 + 7x = 7(1 + x) + 1
8 + 7x = (1 * 7 + x * 7) + 1
8 + 7x = (7 + 7x) + 1

Reorder the terms:
8 + 7x = 7 + 1 + 7x

Combine like terms: 7 + 1 = 8
8 + 7x = 8 + 7x

Add '-8' to each side of the equation.
8 + -8 + 7x = 8 + -8 + 7x

Combine like terms: 8 + -8 = 0
0 + 7x = 8 + -8 + 7x
7x = 8 + -8 + 7x

Combine like terms: 8 + -8 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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