4(x+2)+4=2+6(x+1)

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Solution for 4(x+2)+4=2+6(x+1) equation: 



4(x+2)+4=2+6(x+1)

We move all terms to the left:

4(x+2)+4-(2+6(x+1))=0

We multiply parentheses

4x-(2+6(x+1))+8+4=0



We calculate terms in parentheses: -(2+6(x+1)), so:

2+6(x+1)

determiningTheFunctionDomain
6(x+1)+2

We multiply parentheses

6x+6+2

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

4x-(6x+8)+12=0

We get rid of parentheses

4x-6x-8+12=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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