4(x+2)+x+1=2x-3+(x+4)

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Solution for 4(x+2)+x+1=2x-3+(x+4) equation: 



4(x+2)+x+1=2x-3+(x+4)

We move all terms to the left:

4(x+2)+x+1-(2x-3+(x+4))=0

We add all the numbers together, and all the variables

x+4(x+2)-(2x-3+(x+4))+1=0

We multiply parentheses

x+4x-(2x-3+(x+4))+8+1=0



We calculate terms in parentheses: -(2x-3+(x+4)), so:

2x-3+(x+4)

determiningTheFunctionDomain
2x+(x+4)-3

We get rid of parentheses

2x+x+4-3

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

5x-(3x+1)+9=0

We get rid of parentheses

5x-3x-1+9=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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