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4(x+2)-10=2(x+1)
We move all terms to the left:
4(x+2)-10-(2(x+1))=0
We multiply parentheses
4x-(2(x+1))+8-10=0
We calculate terms in parentheses: -(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
4x-(2x+2)-2=0
We get rid of parentheses
4x-2x-2-2=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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