4(x+2)-1=3x-4(x+1)

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Solution for 4(x+2)-1=3x-4(x+1) equation: 



4(x+2)-1=3x-4(x+1)

We move all terms to the left:

4(x+2)-1-(3x-4(x+1))=0

We multiply parentheses

4x-(3x-4(x+1))+8-1=0



We calculate terms in parentheses: -(3x-4(x+1)), so:

3x-4(x+1)

We multiply parentheses

3x-4x-4

We add all the numbers together, and all the variables

-1x-4

Back to the equation:

-(-1x-4)



We add all the numbers together, and all the variables

4x-(-1x-4)+7=0

We get rid of parentheses

4x+1x+4+7=0

We add all the numbers together, and all the variables

5x+11=0

We move all terms containing x to the left, all other terms to the right

5x=-11

x=-11/5

x=-2+1/5

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