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4(x+2)-2=2(2x+1)
We move all terms to the left:
4(x+2)-2-(2(2x+1))=0
We multiply parentheses
4x-(2(2x+1))+8-2=0
We calculate terms in parentheses: -(2(2x+1)), so:We add all the numbers together, and all the variables
2(2x+1)
We multiply parentheses
4x+2
Back to the equation:
-(4x+2)
4x-(4x+2)+6=0
We get rid of parentheses
4x-4x-2+6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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