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4(x+2)-2x=10-2(2x+3)
We move all terms to the left:
4(x+2)-2x-(10-2(2x+3))=0
We add all the numbers together, and all the variables
-2x+4(x+2)-(10-2(2x+3))=0
We multiply parentheses
-2x+4x-(10-2(2x+3))+8=0
We calculate terms in parentheses: -(10-2(2x+3)), so:We add all the numbers together, and all the variables
10-2(2x+3)
determiningTheFunctionDomain -2(2x+3)+10
We multiply parentheses
-4x-6+10
We add all the numbers together, and all the variables
-4x+4
Back to the equation:
-(-4x+4)
2x-(-4x+4)+8=0
We get rid of parentheses
2x+4x-4+8=0
We add all the numbers together, and all the variables
6x+4=0
We move all terms containing x to the left, all other terms to the right
6x=-4
x=-4/6
x=-2/3
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