4(x+2)-3(x+1)=3x+2(x+1)+3

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Solution for 4(x+2)-3(x+1)=3x+2(x+1)+3 equation: 



4(x+2)-3(x+1)=3x+2(x+1)+3

We move all terms to the left:

4(x+2)-3(x+1)-(3x+2(x+1)+3)=0

We multiply parentheses

4x-3x-(3x+2(x+1)+3)+8-3=0



We calculate terms in parentheses: -(3x+2(x+1)+3), so:

3x+2(x+1)+3

We multiply parentheses

3x+2x+2+3

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

x-(5x+5)+5=0

We get rid of parentheses

x-5x-5+5=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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