4(x+2)-3(x-2)=20

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Solution for 4(x+2)-3(x-2)=20 equation: 



4(x+2)-3(x-2)=20

We move all terms to the left:

4(x+2)-3(x-2)-(20)=0

We multiply parentheses

4x-3x+8+6-20=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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