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4(x+2)-4=2(x+2)-12
We move all terms to the left:
4(x+2)-4-(2(x+2)-12)=0
We multiply parentheses
4x-(2(x+2)-12)+8-4=0
We calculate terms in parentheses: -(2(x+2)-12), so:We add all the numbers together, and all the variables
2(x+2)-12
We multiply parentheses
2x+4-12
We add all the numbers together, and all the variables
2x-8
Back to the equation:
-(2x-8)
4x-(2x-8)+4=0
We get rid of parentheses
4x-2x+8+4=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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