4(x+2)-5(x-1)=3(3+4x)-20

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Solution for 4(x+2)-5(x-1)=3(3+4x)-20 equation: 



4(x+2)-5(x-1)=3(3+4x)-20

We move all terms to the left:

4(x+2)-5(x-1)-(3(3+4x)-20)=0

We add all the numbers together, and all the variables

4(x+2)-5(x-1)-(3(4x+3)-20)=0

We multiply parentheses

4x-5x-(3(4x+3)-20)+8+5=0



We calculate terms in parentheses: -(3(4x+3)-20), so:

3(4x+3)-20

We multiply parentheses

12x+9-20

We add all the numbers together, and all the variables

12x-11

Back to the equation:

-(12x-11)



We add all the numbers together, and all the variables

-1x-(12x-11)+13=0

We get rid of parentheses

-1x-12x+11+13=0

We add all the numbers together, and all the variables

-13x+24=0

We move all terms containing x to the left, all other terms to the right

-13x=-24

x=-24/-13

x=1+11/13

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