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4(x+2)-x=2(x-1)+1
We move all terms to the left:
4(x+2)-x-(2(x-1)+1)=0
We add all the numbers together, and all the variables
-1x+4(x+2)-(2(x-1)+1)=0
We multiply parentheses
-1x+4x-(2(x-1)+1)+8=0
We calculate terms in parentheses: -(2(x-1)+1), so:We add all the numbers together, and all the variables
2(x-1)+1
We multiply parentheses
2x-2+1
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
3x-(2x-1)+8=0
We get rid of parentheses
3x-2x+1+8=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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