4(x+2)/3=6(x-7)/7=12

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Solution for 4(x+2)/3=6(x-7)/7=12 equation: 



4(x+2)/3=6(x-7)/7=12

We move all terms to the left:

4(x+2)/3-(6(x-7)/7)=0

We calculate fractions


4x/()+(-(6(x-7)*3)/()=0



We calculate terms in parentheses: +(-(6(x-7)*3)/(), so:

-(6(x-7)*3)/(

We multiply all the terms by the denominator


-(6(x-7)*3)



We calculate terms in parentheses: -(6(x-7)*3), so:

6(x-7)*3

We multiply parentheses

18x-126

Back to the equation:

-(18x-126)



We get rid of parentheses

-18x+126

Back to the equation:

+(-18x+126)



We get rid of parentheses

4x/()-18x+126=0

We multiply all the terms by the denominator


4x-18x*()+126*()=0

We add all the numbers together, and all the variables

4x-18x*()=0

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