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4(x+2)/3=x-1
We move all terms to the left:
4(x+2)/3-(x-1)=0
We get rid of parentheses
4(x+2)/3-x+1=0
We multiply all the terms by the denominator
4(x+2)-x*3+1*3=0
We add all the numbers together, and all the variables
4(x+2)-x*3+3=0
We multiply parentheses
4x-x*3+8+3=0
Wy multiply elements
4x-3x+8+3=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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