4(x+2)=(2x)2+8x

Solution for 4(x+2)=(2x)2+8x equation:

4(x+2)=(2x)2+8x

We move all terms to the left:

4(x+2)-((2x)2+8x)=0

We add all the numbers together, and all the variables

-(+2x^2+8x)+4(x+2)=0

We multiply parentheses

-(+2x^2+8x)+4x+8=0

We get rid of parentheses

-2x^2-8x+4x+8=0

We add all the numbers together, and all the variables

-2x^2-4x+8=0

a = -2; b = -4; c = +8;
Δ = b2-4ac
Δ = -42-4·(-2)·8
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{5}}{2*-2}=\frac{4-4\sqrt{5}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{5}}{2*-2}=\frac{4+4\sqrt{5}}{-4}
$