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4(x+2)=1/2(10x-20)
We move all terms to the left:
4(x+2)-(1/2(10x-20))=0
Domain of the equation: 2(10x-20))!=0We multiply parentheses
x∈R
4x-(1/2(10x-20))+8=0
We multiply all the terms by the denominator
4x*2(10x-20))-(1+8*2(10x-20))=0
Wy multiply elements
8x^2(1+16x(1=0
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