4(x+2)=2(3x+2)+2(x+-1)

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Solution for 4(x+2)=2(3x+2)+2(x+-1) equation: 



4(x+2)=2(3x+2)+2(x+-1)

We move all terms to the left:

4(x+2)-(2(3x+2)+2(x+-1))=0

We add all the numbers together, and all the variables

4(x+2)-(2(3x+2)+2(x-1))=0

We multiply parentheses

4x-(2(3x+2)+2(x-1))+8=0



We calculate terms in parentheses: -(2(3x+2)+2(x-1)), so:

2(3x+2)+2(x-1)

We multiply parentheses

6x+2x+4-2

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

4x-8x-2+8=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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