4(x+2)=2(x-1)+16

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Solution for 4(x+2)=2(x-1)+16 equation: 



4(x+2)=2(x-1)+16

We move all terms to the left:

4(x+2)-(2(x-1)+16)=0

We multiply parentheses

4x-(2(x-1)+16)+8=0



We calculate terms in parentheses: -(2(x-1)+16), so:

2(x-1)+16

We multiply parentheses

2x-2+16

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We get rid of parentheses

4x-2x-14+8=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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