4(x+2)=20(x-6)

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Solution for 4(x+2)=20(x-6) equation: 



4(x+2)=20(x-6)

We move all terms to the left:

4(x+2)-(20(x-6))=0

We multiply parentheses

4x-(20(x-6))+8=0



We calculate terms in parentheses: -(20(x-6)), so:

20(x-6)

We multiply parentheses

20x-120

Back to the equation:

-(20x-120)



We get rid of parentheses

4x-20x+120+8=0

We add all the numbers together, and all the variables

-16x+128=0

We move all terms containing x to the left, all other terms to the right

-16x=-128

x=-128/-16

x=+8

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