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4(x+2)=3(x-1)+3
We move all terms to the left:
4(x+2)-(3(x-1)+3)=0
We multiply parentheses
4x-(3(x-1)+3)+8=0
We calculate terms in parentheses: -(3(x-1)+3), so:We add all the numbers together, and all the variables
3(x-1)+3
We multiply parentheses
3x-3+3
We add all the numbers together, and all the variables
3x
Back to the equation:
-(3x)
x+8=0
We move all terms containing x to the left, all other terms to the right
x=-8
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