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4(x+2)=3x(x-1)
We move all terms to the left:
4(x+2)-(3x(x-1))=0
We multiply parentheses
4x-(3x(x-1))+8=0
We calculate terms in parentheses: -(3x(x-1)), so:We get rid of parentheses
3x(x-1)
We multiply parentheses
3x^2-3x
Back to the equation:
-(3x^2-3x)
-3x^2+4x+3x+8=0
We add all the numbers together, and all the variables
-3x^2+7x+8=0
a = -3; b = 7; c = +8;
Δ = b2-4ac
Δ = 72-4·(-3)·8
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{145}}{2*-3}=\frac{-7-\sqrt{145}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{145}}{2*-3}=\frac{-7+\sqrt{145}}{-6} $
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